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-6x^2-2x=-3
We move all terms to the left:
-6x^2-2x-(-3)=0
We add all the numbers together, and all the variables
-6x^2-2x+3=0
a = -6; b = -2; c = +3;
Δ = b2-4ac
Δ = -22-4·(-6)·3
Δ = 76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{76}=\sqrt{4*19}=\sqrt{4}*\sqrt{19}=2\sqrt{19}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{19}}{2*-6}=\frac{2-2\sqrt{19}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{19}}{2*-6}=\frac{2+2\sqrt{19}}{-12} $
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